ECMA-334 C# Language Specification10.5.4: Accessibility constraints |
Several constructs in the C# language require a type to be at least as accessible as a member or another type. A type T is said to be at least as accessible as a member or type M if the accessibility domain of T is a superset of the accessibility domain of M. In other words, T is at least as accessible as M if T is accessible in all contexts in which M is accessible.
The following accessibility constraints exist:
- The direct base class of a class type must be at least as accessible as the class type itself.
- The explicit base interfaces of an interface type must be at least as accessible as the interface type itself.
- The return type and parameter types of a delegate type must be at least as accessible as the delegate type itself.
- The type of a constant must be at least as accessible as the constant itself.
- The type of a field must be at least as accessible as the field itself.
- The return type and parameter types of a method must be at least as accessible as the method itself.
- The type of a property must be at least as accessible as the property itself.
- The type of an event must be at least as accessible as the event itself.
- The type and parameter types of an indexer must be at least as accessible as the indexer itself.
- The return type and parameter types of an operator must be at least as accessible as the operator itself.
- The parameter types of an instance constructor must be at least as accessible as the instance constructor itself.
[Example: In the example
class A {...}
public class B: A {...}
|
the B class results in a compile-time error because A is not at least as accessible as B. end example]
[Example: Likewise, in the example
class A {...}
public class B
{
A F() {...}
internal A G() {...}
public A H() {...}
}
|
the H method in B results in a compile-time error because the return type A is not at least as accessible as the method. end example]